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人気のある微分積分 >

integral from 1 to 2 of (x^2+2x)

解

\int_{1}^{2} (x^{2} + 2 x) d x

解

\frac{16}{3}

+1

十進法表記

5.33333 \dots

解答ステップ

\int_{1}^{2} x^{2} + 2 x d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{2} d x + \int_{1}^{2} 2 x d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} 2 x d x = 3

= \frac{7}{3} + 3

簡素化

\frac{7}{3} + 3 : \frac{16}{3}

= \frac{16}{3}

グラフ

人気の例

tangent f(x)=x^2+x,\at x=-1,2

t an g e n t f (x) = x^{2} + x, at x = - 1, 2

integral from-2 to 1 of (x^2-6x+12)

\int_{- 2}^{1} (x^{2} - 6 x + 12) d x

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\int (sec^{2} (x) + 7) d x

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