What is laplacetransform-6t^2\delta(t-5) ?

The answer to laplacetransform-6t^2\delta(t-5) is -150e^{-5s}

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laplacetransform-6t^2\delta(t-5)

laplace transform

- 6 t^{2} δ (t - 5)

- 150 e^{- 5 s}

Solution steps

L {- 6 t^{2} δ (t - 5)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 6 L {t^{2} δ (t - 5)}

L {t^{2} δ (t - 5)} : 25 e^{- 5 s}

= - 6 \cdot 25 e^{- 5 s}

Refine

- 625 e^{- 5 s} : - 150 e^{- 5 s}

= - 150 e^{- 5 s}

5 - 5 x^{3}

\frac{d}{d x} (\frac{2 x}{7 - cot ( x )})

1 (t)

\int 26 arctan (x) d x

\int e^{x^{2} - 4} + 5 x + 6 d x

What is laplacetransform-6t^2\delta(t-5) ?
The answer to laplacetransform-6t^2\delta(t-5) is -150e^{-5s}