What is the derivative of y=(e^{4x^{2+1}})/8 ?

The derivative of y=(e^{4x^{2+1}})/8 is (3e^{4x^3}x^2)/2

What is the first derivative of y=(e^{4x^{2+1}})/8 ?

The first derivative of y=(e^{4x^{2+1}})/8 is (3e^{4x^3}x^2)/2

derivative of

y = \frac{e ^{4 x^{2 + 1}}}{8}

\frac{3 e ^{4 x^{3}} x ^{2}}{2}

Solution steps

\frac{d}{d x} (\frac{e ^{4 x^{2 + 1}}}{8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d x} (e^{4 x^{2 + 1}})

Apply the chain rule:

e^{4 x^{2 + 1}} \frac{d}{d x} (4 x^{2 + 1})

= e^{4 x^{2 + 1}} \frac{d}{d x} (4 x^{2 + 1})

\frac{d}{d x} (4 x^{2 + 1}) = 12 x^{2}

= \frac{1}{8} e^{4 x^{2 + 1}} \cdot 12 x^{2}

Simplify

\frac{1}{8} e^{4 x^{2 + 1}} \cdot 12 x^{2} : \frac{3 e ^{4 x^{3}} x ^{2}}{2}

= \frac{3 e ^{4 x^{3}} x ^{2}}{2}

\frac{\partial}{\partial y} (x^{2} y^{4} + z^{3})

x \to 7 lim (18)

\int ln (\frac{x}{x + 1}) d x

\int_{0}^{4} x^{2} - 4 x + 3 d x

\frac{d}{d x} (d - b - a x - \frac{d}{x ^{2}})

What is the derivative of y=(e^{4x^{2+1}})/8 ?
The derivative of y=(e^{4x^{2+1}})/8 is (3e^{4x^3}x^2)/2
What is the first derivative of y=(e^{4x^{2+1}})/8 ?
The first derivative of y=(e^{4x^{2+1}})/8 is (3e^{4x^3}x^2)/2