What is the integral of (1-x)^2sqrt(x) ?

The integral of (1-x)^2sqrt(x) is 2/3 x^{3/2}-4/5 x^{5/2}+2/7 x^{7/2}+C

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integral of (1-x)^2sqrt(x)

\int (1 - x)^{2} x d x

\frac{2}{3} x^{\frac{3}{2}} - \frac{4}{5} x^{\frac{5}{2}} + \frac{2}{7} x^{\frac{7}{2}} + C

Solution steps

\int (1 - x)^{2} x d x

Expand

(1 - x)^{2} x : x - 2 x^{\frac{3}{2}} + x^{\frac{5}{2}}

= \int x - 2 x^{\frac{3}{2}} + x^{\frac{5}{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x - \int 2 x^{\frac{3}{2}} d x + \int x^{\frac{5}{2}} d x

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

\int 2 x^{\frac{3}{2}} d x = \frac{4}{5} x^{\frac{5}{2}}

\int x^{\frac{5}{2}} d x = \frac{2}{7} x^{\frac{7}{2}}

= \frac{2}{3} x^{\frac{3}{2}} - \frac{4}{5} x^{\frac{5}{2}} + \frac{2}{7} x^{\frac{7}{2}}

Add a constant to the solution

= \frac{2}{3} x^{\frac{3}{2}} - \frac{4}{5} x^{\frac{5}{2}} + \frac{2}{7} x^{\frac{7}{2}} + C

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y (0) = 7, y^{^{'}} (0) = 0

- 1.5 sin (1.5 x)

\int (9 x - 1) e^{- x} d x

\int (x + 6)^{2} d x

What is the integral of (1-x)^2sqrt(x) ?
The integral of (1-x)^2sqrt(x) is 2/3 x^{3/2}-4/5 x^{5/2}+2/7 x^{7/2}+C