What is t/(sqrt(t^2+1)) ?

The solution to t/(sqrt(t^2+1)) is (tsqrt(t^2+1))/(t^2+1)

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simplify t/(sqrt(t^2+1))

simplify

\frac{t}{t ^{2} + 1}

\frac{t t ^{2} + 1}{t ^{2} + 1}

Solution steps

\frac{t}{t ^{2} + 1}

Multiply by the conjugate

\frac{t ^{2} + 1}{t ^{2} + 1}

= \frac{t t ^{2} + 1}{t ^{2} + 1 t ^{2} + 1}

t^{2} + 1 t^{2} + 1 = t^{2} + 1

= \frac{t t ^{2} + 1}{t ^{2} + 1}

y^{^{''}} + 15 y^{^{'}} + 56 y = 0

\frac{d y}{d x} + 9 y = 5

t^{2} y^{^{'}} + y^{2} = t y

(3 x^{2} + x) (5 x^{3} + 1)

\int \frac{- 1}{e ^{x}} d x

What is t/(sqrt(t^2+1)) ?
The solution to t/(sqrt(t^2+1)) is (tsqrt(t^2+1))/(t^2+1)