What is the derivative of f(x)=x^7-1(x) ?

The derivative of f(x)=x^7-1(x) is 7x^6-1

What is the first derivative of f(x)=x^7-1(x) ?

The first derivative of f(x)=x^7-1(x) is 7x^6-1

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derivative of

f (x) = x^{7} - 1 (x)

7 x^{6} - 1

Solution steps

\frac{d}{d x} (x^{7} - 1 \cdot x)

Simplify

x^{7} - 1 \cdot x : x^{7} - x

= \frac{d}{d x} (x^{7} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{7}) - \frac{d x}{d x}

\frac{d}{d x} (x^{7}) = 7 x^{6}

\frac{d x}{d x} = 1

= 7 x^{6} - 1

\int r 2 - r^{2} d r

\int \frac{1}{( 4 x + 1 ) 16 x ^{2} + 4} d x

f (x) = - 1 - 8 x^{2}, at x = - 2

\int_{0}^{1} (x) - (x^{2}) d x

\int (x - 7)^{2} d x

What is the derivative of f(x)=x^7-1(x) ?
The derivative of f(x)=x^7-1(x) is 7x^6-1
What is the first derivative of f(x)=x^7-1(x) ?
The first derivative of f(x)=x^7-1(x) is 7x^6-1