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Popular >

integral from 0 to 4 of-x+1

Solution

\int_{0}^{4} - x + 1 d x

Solution

- 4

Solution steps

\int_{0}^{4} - x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{4} x d x + \int_{0}^{4} 1 d x

\int_{0}^{4} x d x = 8

\int_{0}^{4} 1 d x = 4

= - 8 + 4

Simplify

= - 4

Popular Examples

limit as x approaches infinity of (sqrt(x))/(6+e^x)

x \to \infty lim (\frac{x}{6 + e ^{x}})

integral of ((4-t+t^2)/(t^2))

\int (\frac{4 - t + t ^{2}}{t ^{2}}) d t

derivative of ln(sqrt(x^2+20))

\frac{d}{d x} (ln (x^{2} + 20))

(\partial)/(\partial x)((2y)/(x^2+1))

\frac{\partial}{\partial x} (\frac{2 y}{x ^{2} + 1})

limit as x approaches 3 of (x-2)/(x+2)

x \to 3 lim (\frac{x - 2}{x + 2})

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of-x+1 ?
The integral from 0 to 4 of-x+1 is -4