What is the derivative of-3x^2+2x+2 ?

The derivative of-3x^2+2x+2 is -6x+2

What is the first derivative of-3x^2+2x+2 ?

The first derivative of-3x^2+2x+2 is -6x+2

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\frac{d}{d x} (- 3 x^{2} + 2 x + 2)

- 6 x + 2

Solution steps

\frac{d}{d x} (- 3 x^{2} + 2 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (2) = 0

= - 6 x + 2 + 0

Simplify

= - 6 x + 2

4 e^{\frac{2 t}{3}}

x \to 0 lim (\frac{6 sin ( 3 x )}{x})

\frac{d}{d x} (3^{2 x^{2}} x)

\int_{t}^{2} (\frac{1}{x - 1}) d x

\int 3^{2} d x

What is the derivative of-3x^2+2x+2 ?
The derivative of-3x^2+2x+2 is -6x+2
What is the first derivative of-3x^2+2x+2 ?
The first derivative of-3x^2+2x+2 is -6x+2