What is the derivative of (3x^2+1/(2x)) ?

The derivative of (3x^2+1/(2x)) is (3x^2-1)/(2x^2)

What is the first derivative of (3x^2+1/(2x)) ?

The first derivative of (3x^2+1/(2x)) is (3x^2-1)/(2x^2)

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\frac{d}{d x} (\frac{3 x ^{2} + 1}{2 x})

\frac{3 x ^{2} - 1}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x ^{2} + 1}{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{3 x ^{2} + 1}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{2} \cdot \frac{\frac{d}{d x} ( 3 x ^{2} + 1 ) x - \frac{d x}{d x} ( 3 x ^{2} + 1 )}{x ^{2}}

\frac{d}{d x} (3 x^{2} + 1) = 6 x

\frac{d x}{d x} = 1

= \frac{1}{2} \cdot \frac{6 xx - 1 \cdot ( 3 x ^{2} + 1 )}{x ^{2}}

Simplify

\frac{1}{2} \cdot \frac{6 xx - 1 \cdot ( 3 x ^{2} + 1 )}{x ^{2}} : \frac{3 x ^{2} - 1}{2 x ^{2}}

= \frac{3 x ^{2} - 1}{2 x ^{2}}

\int sin^{3} (b) cos^{3} (b)

x \to - 2 lim (x^{4} + 5^{x} - 2)

\frac{\partial}{\partial y} (x ln (x + 2 y + 3 z))

\frac{\partial}{\partial x} (\frac{x ^{3}}{3})

x \to 0 lim (4 x^{2})

What is the derivative of (3x^2+1/(2x)) ?
The derivative of (3x^2+1/(2x)) is (3x^2-1)/(2x^2)
What is the first derivative of (3x^2+1/(2x)) ?
The first derivative of (3x^2+1/(2x)) is (3x^2-1)/(2x^2)