What is the solution for y(x+1)+(dy)/(dx)=0 ?

The solution for y(x+1)+(dy)/(dx)=0 is y=e^{-(x^2)/2-x+c_{1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y(x+1)+(dy)/(dx)=0

y (x + 1) + \frac{d y}{d x} = 0

y = e^{- \frac{x ^{2}}{2} - x + c_{1}}

Solution steps

y (x + 1) + \frac{d y}{d x} = 0

Solve separable ODE:

y = e^{- \frac{x ^{2}}{2} - x + c_{1}}

y = e^{- \frac{x ^{2}}{2} - x + c_{1}}

6 - x^{2}

\int_{- y}^{y} x d x

\frac{d}{d x} (2 x e^{- 3 x})

\frac{d}{d x} (x^{6} (x - 4)^{5})

\frac{d}{d x} ((1 - 2 x)^{3})

What is the solution for y(x+1)+(dy)/(dx)=0 ?
The solution for y(x+1)+(dy)/(dx)=0 is y=e^{-(x^2)/2-x+c_{1}}