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人気のある微分積分 >

(\partial)/(\partial x)(2sin(2x))

解

\frac{\partial}{\partial x} (2 sin (2 x))

解

4 cos (2 x)

解答ステップ

\frac{\partial}{\partial x} (2 sin (2 x))

定数を除去:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (sin (2 x))

連鎖法則を適用:

cos (2 x) \frac{\partial}{\partial x} (2 x)

= cos (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= 2 cos (2 x) \cdot 2

簡素化

= 4 cos (2 x)

人気の例

derivative sqrt(5t)

d er i v a t i v e 5 t

derivative of 1/(x^2(3x+1))

\frac{d}{d x} (\frac{1}{x ^{2} ( 3 x + 1 )})

(\partial)/(\partial x)(xy^2cos(2+x^2y))

\frac{\partial}{\partial x} (x y^{2} cos (2 + x^{2} y))

面積 2sin(x),[0,pi]

a re a 2 sin (x), [0, π]

tangent f(x)= 5/(2sqrt(5x+6)),\at x=6

t an g e n t f (x) = \frac{5}{2 5 x + 6}, at x = 6