What is the sum from n=1 to infinity of ((1)^n)/n ?

The sum from n=1 to infinity of ((1)^n)/n is diverges

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sum from n=1 to infinity of ((1)^n)/n

n = 1 \sum \infty \frac{( 1 ) ^{n}}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{1 ^{n}}{n}

Simplify

= n = 1 \sum \infty \frac{1}{n}

Apply Cauchy's Convergence Condition:

diverges

= diverges

n = 0 \sum \infty \frac{17}{2}

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\frac{d}{d x} ((2 x + 1)^{4} + 8 x (2 x + 1)^{3})

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What is the sum from n=1 to infinity of ((1)^n)/n ?
The sum from n=1 to infinity of ((1)^n)/n is diverges