What is the sum from n=0 to infinity of 1/(3^{n+1)} ?

The sum from n=0 to infinity of 1/(3^{n+1)} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of 1/(3^{n+1)}

n = 0 \sum \infty \frac{1}{3 ^{n + 1}}

converges

Solution steps

n = 0 \sum \infty \frac{1}{3 ^{n + 1}}

Apply Series Ratio Test:

converges

= converges

\int tan^{3} (2 t) sec^{3} (2 t) d t

\frac{d ^{2}}{d x ^{2}} (cos^{2} (2 π x))

\int x^{3} d x

ln (x^{2} + 1)

\int_{- 2}^{0} \frac{x}{2} + 1 d x

What is the sum from n=0 to infinity of 1/(3^{n+1)} ?
The sum from n=0 to infinity of 1/(3^{n+1)} is converges