What is the integral from 0 to a of 7xsqrt(a^2-x^2) ?

The integral from 0 to a of 7xsqrt(a^2-x^2) is (7(a^2)^{3/2})/3

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integral from 0 to a of 7xsqrt(a^2-x^2)

\int_{0}^{a} 7 x a^{2} - x^{2} d x

\frac{7 ( a ^{2} ) ^{\frac{3}{2}}}{3}

Solution steps

\int_{0}^{a} 7 x a^{2} - x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int_{0}^{a} x a^{2} - x^{2} d x

Apply u-substitution

: \int_{a^{2}}^{0} - \frac{u}{2} d u

= 7 \cdot \int_{a^{2}}^{0} - \frac{u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 (- \frac{1}{2} \cdot \int_{a^{2}}^{0} u d u)

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{a^{2}}^{0}

= 7 (- \frac{1}{2} [\frac{2}{3} u^{\frac{3}{2}}]_{a^{2}}^{0})

Simplify

7 (- \frac{1}{2} [\frac{2}{3} u^{\frac{3}{2}}]_{a^{2}}^{0}) : - \frac{7}{2} [\frac{2}{3} u^{\frac{3}{2}}]_{a^{2}}^{0}

= - \frac{7}{2} [\frac{2}{3} u^{\frac{3}{2}}]_{a^{2}}^{0}

Compute the boundaries:

- \frac{2}{3} (a^{2})^{\frac{3}{2}}

= - \frac{7}{2} (- \frac{2}{3} (a^{2})^{\frac{3}{2}})

Simplify

= \frac{7 ( a ^{2} ) ^{\frac{3}{2}}}{3}

\frac{a x}{x ^{2} + a ^{2}}

\frac{d y}{d x} + 2 x y = - x y^{4}

\frac{d}{d x} (x^{2} e^{- x^{3}})

\frac{d}{d x} (2 x - 2)

\frac{d}{d x} (3 x^{2} - 10 x + 7)

What is the integral from 0 to a of 7xsqrt(a^2-x^2) ?
The integral from 0 to a of 7xsqrt(a^2-x^2) is (7(a^2)^{3/2})/3