What is the integral of (1-cos(x))^3sin(x) ?

The integral of (1-cos(x))^3sin(x) is ((1-cos(x))^4)/4+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (1-cos(x))^3sin(x)

\int (1 - cos (x))^{3} sin (x) d x

\frac{( 1 - cos ( x ) ) ^{4}}{4} + C

Solution steps

\int (1 - cos (x))^{3} sin (x) d x

Apply u-substitution

: \int u^{3} d u

= \int u^{3} d u

Apply the Power Rule

: \frac{u ^{4}}{4}

= \frac{u ^{4}}{4}

Substitute back

u = 1 - cos (x)

= \frac{( 1 - cos ( x ) ) ^{4}}{4}

Add a constant to the solution

= \frac{( 1 - cos ( x ) ) ^{4}}{4} + C

\int x 4 - x^{2} d x

\frac{\partial}{\partial x} (\frac{a}{a - x})

y = \frac{( x + 3 ) ( x ^{2} - 3 x + 9 )}{x ^{3}}

ln (x + 6)

y^{^{'}} = 9 y^{2} + x y^{2}

What is the integral of (1-cos(x))^3sin(x) ?
The integral of (1-cos(x))^3sin(x) is ((1-cos(x))^4)/4+C