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Popular >

y^'+2y=5

Solution

y^{^{'}} + 2 y = 5

Solution

y = - \frac{e ^{- 2 t - c_{1}}}{2} + \frac{5}{2}

Solution steps

y^{'} (t) + 2 y = 5

Solve separable ODE:

y = - \frac{e ^{- 2 t - c_{1}}}{2} + \frac{5}{2}

y = - \frac{e ^{- 2 t - c_{1}}}{2} + \frac{5}{2}

Popular Examples

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\int_{1}^{3} 3 x^{2} d x

xy^'+3y=((2e^{-4x}))/(x^2)

x y^{^{'}} + 3 y = \frac{( 2 e ^{- 4 x} )}{x ^{2}}

derivative of y(1+e^x)

\frac{d}{d x} (y (1 + e^{x}))

limit as x approaches 1 of 0.99^{2-1}

x \to 1 lim (0.9 9^{2 - 1})

Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=5 ?
The solution for y^'+2y=5 is y=-(e^{-2t-c_{1}})/2+5/2