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Popular >

y^'+3y=4e^{-t}

Solution

y^{^{'}} + 3 y = 4 e^{- t}

Solution

y = \frac{2}{e ^{t}} + \frac{c _{1}}{e ^{3 t}}

Solution steps

y^{'} (t) + 3 y = 4 e^{- t}

Solve linear ODE:

y = \frac{2}{e ^{t}} + \frac{c _{1}}{e ^{3 t}}

y = \frac{2}{e ^{t}} + \frac{c _{1}}{e ^{3 t}}

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f (x) = - x^{2} - 4 x - 6, at x = 4

integral of cos((pit)/2)

\int cos (\frac{π t}{2}) d t

derivative of \sqrt[3]{10+13pi}

Frequently Asked Questions (FAQ)

What is the solution for y^'+3y=4e^{-t} ?
The solution for y^'+3y=4e^{-t} is y= 2/(e^t)+(c_{1})/(e^{3t)}