What is the derivative of f(x)=x^3+4x^2+3x ?

The derivative of f(x)=x^3+4x^2+3x is 3x^2+8x+3

What is the first derivative of f(x)=x^3+4x^2+3x ?

The first derivative of f(x)=x^3+4x^2+3x is 3x^2+8x+3

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derivative of

f (x) = x^{3} + 4 x^{2} + 3 x

3 x^{2} + 8 x + 3

Solution steps

\frac{d}{d x} (x^{3} + 4 x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (3 x) = 3

= 3 x^{2} + 8 x + 3

\int \frac{9 - x ^{2}}{x} d x

\frac{d}{d x} ((x - 1) (x^{2} + 2)^{3})

\frac{\partial}{\partial x} (ln (2 + x^{2} y^{2}))

\int \frac{6 x ^{3}}{x ^{2} + 9} d x

t \to - 1 lim (t^{2} - 1)

What is the derivative of f(x)=x^3+4x^2+3x ?
The derivative of f(x)=x^3+4x^2+3x is 3x^2+8x+3
What is the first derivative of f(x)=x^3+4x^2+3x ?
The first derivative of f(x)=x^3+4x^2+3x is 3x^2+8x+3