What is area y=2-e^x,y=10e^{-x}-5 ?

The answer to area y=2-e^x,y=10e^{-x}-5 is 7ln(5)-7ln(2)-6

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area y=2-e^x,y=10e^{-x}-5

area

y = 2 - e^{x}, y = 10 e^{- x} - 5

7 ln (5) - 7 ln (2) - 6

Solution steps

Apply the area formula:

\int_{l n (2)}^{l n (5)} 2 - e^{x} - (10 e^{- x} - 5) d x

Solve

\int_{l n (2)}^{l n (5)} 2 - e^{x} - (10 e^{- x} - 5) d x : 7 ln (5) - 7 ln (2) - 6

The area is:

= 7 ln (5) - 7 ln (2) - 6

f (x) = \frac{ln ( 4 )}{3} e^{x}

y = \frac{5 x - 2}{x}

8 x^{- 2}

\int - x d x

x \to 0 lim (arccot (\frac{1}{x}))

What is area y=2-e^x,y=10e^{-x}-5 ?
The answer to area y=2-e^x,y=10e^{-x}-5 is 7ln(5)-7ln(2)-6