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Popular >

y^'-(4y)/x =-2/(x^2)

Solution

y^{^{'}} - \frac{4 y}{x} = - \frac{2}{x ^{2}}

Solution

y = \frac{2}{5 x} + c_{1} x^{4}

Solution steps

y^{'} (x) - \frac{4 y}{x} = - \frac{2}{x ^{2}}

Solve linear ODE:

y = \frac{2}{5 x} + c_{1} x^{4}

y = \frac{2}{5 x} + c_{1} x^{4}

Popular Examples

tangent of (-6x)/(x^2+1)tangent of

\frac{- 6 x}{x ^{2} + 1}

\frac{d}{d y} (2 y^{3})

integral of (sqrt(x^3-2))/x

\int \frac{x ^{3} - 2}{x} d x

derivative of f(x)=(1-2t)/(1+6t)derivative of

f (x) = \frac{1 - 2 t}{1 + 6 t}

derivative of f(x)=(5x)/(7x^2+1)derivative of

f (x) = \frac{5 x}{7 x ^{2} + 1}

Frequently Asked Questions (FAQ)

What is the solution for y^'-(4y)/x =-2/(x^2) ?
The solution for y^'-(4y)/x =-2/(x^2) is y= 2/(5x)+c_{1}x^4