What is the d/(d{r)}(sqrt(4-{r)^2}) ?

The d/(d{r)}(sqrt(4-{r)^2}) is -({r})/(sqrt(4-{r)^2)}

What is the first d/(d{r)}(sqrt(4-{r)^2}) ?

The first d/(d{r)}(sqrt(4-{r)^2}) is -({r})/(sqrt(4-{r)^2)}

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\frac{d}{d r} (4 - r^{2})

- \frac{r}{4 - r ^{2}}

Solution steps

\frac{d}{d r} (4 - r^{2})

Apply the chain rule:

\frac{1}{2 4 - r ^{2}} \frac{d}{d r} (4 - r^{2})

= \frac{1}{2 4 - r ^{2}} \frac{d}{d r} (4 - r^{2})

\frac{d}{d r} (4 - r^{2}) = - 2 r

= \frac{1}{2 4 - r ^{2}} (- 2 r)

Simplify

\frac{1}{2 4 - r ^{2}} (- 2 r) : - \frac{r}{4 - r ^{2}}

= - \frac{r}{4 - r ^{2}}

\int x (3 sec^{2} (x) + 2 tan^{2} (x)) d x

t an g e n t y = 7 4 x^{3}

3 y^{^{''}} + 2 y = x^{2} e^{- 3 x}

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} + x + 1})

t an g e n t y = ln (1 - x^{2} + 2 x^{4}), at x = 1

What is the d/(d{r)}(sqrt(4-{r)^2}) ?
The d/(d{r)}(sqrt(4-{r)^2}) is -({r})/(sqrt(4-{r)^2)}
What is the first d/(d{r)}(sqrt(4-{r)^2}) ?
The first d/(d{r)}(sqrt(4-{r)^2}) is -({r})/(sqrt(4-{r)^2)}