en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=y-k

Solution

y^{^{'}} = y - k

Solution

y = e^{t + c_{1}} + k

Solution steps

y^{'} (t) = y - k

Solve separable ODE:

y = e^{t + c_{1}} + k

y = e^{t + c_{1}} + k

Popular Examples

(x^2-4)((dy)/(dx))+4y=(x+2)^2

(x^{2} - 4) (\frac{d y}{d x}) + 4 y = (x + 2)^{2}

slope of (-7,-7),(-3,6)slope

(- 7, - 7), (- 3, 6)

integral of (cos^4(x))/(sin^6(x))

\int \frac{cos ^{4} ( x )}{sin ^{6} ( x )} d x

integral of-7csc^2(x)

\int - 7 csc^{2} (x) d x

y^{''}+y=k*(e^{(-a*t)}-e^{(-b*t)})

y^{^{''}} + y = k \cdot (e^{(- a \cdot t)} - e^{(- b \cdot t)})

Frequently Asked Questions (FAQ)

What is the solution for y^'=y-k ?
The solution for y^'=y-k is y=e^{t+c_{1}}+k