What is the tangent of f(x)=-9x^2,\at x=2 ?

The tangent of f(x)=-9x^2,\at x=2 is y=-36x+36

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tangent of f(x)=-9x^2,\at x=2

tangent

y = - 36 x + 36

Solution steps

Find the tangent point:

(2, - 36)

Find the slope of

f (x) = - 9 x^{2} : \frac{df ( x )}{d x} = - 18 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 36

Find the line with slope m=

- 36

and passing through

(2, - 36) : y = - 36 x + 36

y = - 36 x + 36

What is the tangent of f(x)=-9x^2,\at x=2 ?
The tangent of f(x)=-9x^2,\at x=2 is y=-36x+36