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Beliebt Rechnen >

(\partial)/(\partial z)(ln(x+z)-yz)

Lösung

\frac{\partial}{\partial z} (ln (x + z) - yz)

Lösung

\frac{1}{x + z} - y

Schritte zur Lösung

\frac{\partial}{\partial z} (ln (x + z) - yz)

Behandle

x, y

als Konstanten

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (ln (x + z)) - \frac{\partial}{\partial z} (yz)

\frac{\partial}{\partial z} (ln (x + z)) = \frac{1}{x + z}

\frac{\partial}{\partial z} (yz) = y

= \frac{1}{x + z} - y

Beliebte Beispiele

y^{^{''}} + 4 y = x

integral of (4x^3+2)/(x^2)

\int \frac{4 x ^{3} + 2}{x ^{2}} d x

(d^2)/(dx^2)(sin(5x))

\frac{d ^{2}}{d x ^{2}} (sin (5 x))

derivative y=cot(1-2x^2)

d er i v a t i v e y = cot (1 - 2 x^{2})

xy^'+3y=(2e^{2x})/(x^2)

x y^{^{'}} + 3 y = \frac{2 e ^{2 x}}{x ^{2}}