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Popular Calculus >

integral of x^2cos(mpix)

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Solution

∫x2cos(mπx)dx

Solution

πm1​x2sin(πmx)−π3m32​(−πmxcos(πmx)+sin(πmx))+C
Solution steps
∫x2cos(mπx)dx
Apply Integration By Parts
=πm1​x2sin(πmx)−∫πm2​xsin(πmx)dx
∫πm2​xsin(πmx)dx=π3m32​(−πmxcos(πmx)+sin(πmx))
=πm1​x2sin(πmx)−π3m32​(−πmxcos(πmx)+sin(πmx))
Add a constant to the solution=πm1​x2sin(πmx)−π3m32​(−πmxcos(πmx)+sin(πmx))+C

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Popular Examples

tangent of sin(5x)+cos(4x)tangent of f(x)= 1/(x+2),\at x=0integral of 9x^3y+3y^2limit as x approaches 0-of 4(1/x-csc(x))derivative of (1/3 (x^2+2)^{3/2})

Frequently Asked Questions (FAQ)

  • What is the integral of x^2cos(mpix) ?

    The integral of x^2cos(mpix) is 1/(pim)x^2sin(pimx)-2/(pi^3m^3)(-pimxcos(pimx)+sin(pimx))+C
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