What is the integral of 1/(sqrt(29-x^2)) ?

The integral of 1/(sqrt(29-x^2)) is arcsin(1/(sqrt(29))x)+C

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integral of 1/(sqrt(29-x^2))

\int \frac{1}{29 - x ^{2}} d x

arcsin (\frac{1}{29} x) + C

Solution steps

\int \frac{1}{29 - x ^{2}} d x

Apply Trigonometric Substitution

= \int 1 d u

Integral of a constant:

\int a d x = a x

= 1 \cdot u

Substitute back

u = arcsin (\frac{1}{29} x)

= 1 \cdot arcsin (\frac{1}{29} x)

Simplify

= arcsin (\frac{1}{29} x)

Add a constant to the solution

= arcsin (\frac{1}{29} x) + C

\frac{d}{d x} (ln (x + 9 + x^{2}))

a re a 2 x + 1, x^{2} - 4 x

\frac{d ^{2}}{d x ^{2}} (\frac{e ^{x}}{5 + e ^{x}})

f (x) = (x^{3} - 2 x^{2} + 3 x + 1)^{11}

\frac{d}{d x} (x - 1 - x^{2})

What is the integral of 1/(sqrt(29-x^2)) ?
The integral of 1/(sqrt(29-x^2)) is arcsin(1/(sqrt(29))x)+C