What is the tangent of f(x)=x^6,\at x=2 ?

The tangent of f(x)=x^6,\at x=2 is y=192x-320

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tangent of f(x)=x^6,\at x=2

tangent of

f (x) = x^{6}, at x = 2

y = 192 x - 320

Solution steps

Find the tangent point:

(2, 64)

Find the slope of

f (x) = x^{6} : \frac{df ( x )}{d x} = 6 x^{5}

Compute the slope of

f (x) = x^{6}

x = 2 : m = 192

Find the line with slope m=

192

and passing through

(2, 64) : y = 192 x - 320

y = 192 x - 320

\frac{d y}{d x} = 1 + x y

\frac{d}{d x} (\frac{2}{x} + 1)

x^{^{'}} = 5 (1 - \frac{x}{10})

y^{^{''}} + 4 y^{^{'}} + 4 y = x cos (2 x) + 3 e^{- 2 x}

\int tan^{3} (6 x) sec^{3} (6 x) d x

What is the tangent of f(x)=x^6,\at x=2 ?
The tangent of f(x)=x^6,\at x=2 is y=192x-320