What is (\partial)/(\partial x)(-6y^2+12xy) ?

The answer to (\partial)/(\partial x)(-6y^2+12xy) is 12y

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(\partial)/(\partial x)(-6y^2+12xy)

\frac{\partial}{\partial x} (- 6 y^{2} + 12 x y)

12 y

Solution steps

\frac{\partial}{\partial x} (- 6 y^{2} + 12 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (6 y^{2}) + \frac{\partial}{\partial x} (12 x y)

\frac{\partial}{\partial x} (6 y^{2}) = 0

\frac{\partial}{\partial x} (12 x y) = 12 y

= - 0 + 12 y

Simplify

= 12 y

\frac{\partial}{\partial x} (\frac{( p ( q , x ) - c q )}{x})

\frac{\partial}{\partial y} (8 z e^{x yz})

f (t) = 4 t - 10

\frac{d}{d x} (\frac{x ^{5}}{7})

\frac{d}{d x} (2 x ln (x) + x^{2} - 1)

What is (\partial)/(\partial x)(-6y^2+12xy) ?
The answer to (\partial)/(\partial x)(-6y^2+12xy) is 12y