What is the solution for (dy)/(dt)+y=te^t ?

The solution for (dy)/(dt)+y=te^t is y=(e^t(2t-1))/4+(c_{1})/(e^t)

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(dy)/(dt)+y=te^t

\frac{d y}{d t} + y = t e^{t}

y = \frac{e ^{t} ( 2 t - 1 )}{4} + \frac{c _{1}}{e ^{t}}

Solution steps

\frac{d y}{d t} + y = t e^{t}

Solve linear ODE:

y = \frac{e ^{t} ( 2 t - 1 )}{4} + \frac{c _{1}}{e ^{t}}

y = \frac{e ^{t} ( 2 t - 1 )}{4} + \frac{c _{1}}{e ^{t}}

f (x) = \frac{1}{2 x}, at x = 36

f (x) = \frac{tan ( 9 x )}{1 + sin ( 9 x )}

(2 x + 3 y - 1) d x - 4 (x + 1) d y = 0

\frac{e ^{- 2 s}}{s ( s - 2 )}

What is the solution for (dy)/(dt)+y=te^t ?
The solution for (dy)/(dt)+y=te^t is y=(e^t(2t-1))/4+(c_{1})/(e^t)