What is the tangent of f(x)=2sqrt(x),\at x=4 ?

The tangent of f(x)=2sqrt(x),\at x=4 is y= 1/2 x+2

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tangent of f(x)=2sqrt(x),\at x=4

tangent of

f (x) = 2 x, at x = 4

y = \frac{1}{2} x + 2

Solution steps

Find the tangent point:

(4, 4)

Find the slope of

f (x) = 2 x : \frac{df ( x )}{d x} = \frac{1}{x}

Compute the slope of

f (x) = 2 x

x = 4 : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(4, 4) : y = \frac{1}{2} x + 2

y = \frac{1}{2} x + 2

y^{^{'}} = \frac{3 x ^{2} + 2 x - 4}{2 y - 4}, y (2) = 0

\frac{2 s}{( s ^{2} + 1 ) ^{2} ( s + 1 )}

\frac{d}{d x} (\frac{x cos ( x ) - sin ( x )}{x ^{2}})

x \to 3 lim (10 (x + 3))

f (x) = 6 x^{2} - 5 x

What is the tangent of f(x)=2sqrt(x),\at x=4 ?
The tangent of f(x)=2sqrt(x),\at x=4 is y= 1/2 x+2