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Beliebt Rechnen >

inverselaplace ((e^{-2s}))/(s+1)

Lösung

inverse laplace transformation

\frac{( e ^{- 2 s} )}{s + 1}

Lösung

H (t - 2) e^{- t + 2}

Schritte zur Lösung

L^{- 1} {\frac{( e ^{- 2 s} )}{s + 1}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {e^{- a s} F (s)} = H (t - a) f (t - a)

Wo

H (t)

Heaviside (Schritt) Funktion ist

= H (t - 2) L^{- 1} {\frac{1}{s + 1}} (t - 2)

L^{- 1} {\frac{1}{s + 1}} : e^{- t}

= H (t - 2) e^{- (t - 2)}

= H (t - 2) e^{- t + 2}

Beliebte Beispiele

derivative of 3sqrt(x-2)

\frac{d}{d x} (3 x - 2)

(\partial)/(\partial x)(2y-2)

\frac{\partial}{\partial x} (2 y - 2)

(\partial)/(\partial x)(x^6+xy^5+7)

\frac{\partial}{\partial x} (x^{6} + x y^{5} + 7)

integral of (cos(x)+xcos(y)-y)

\int (cos (x) + x cos (y) - y) d y

(6 + x) y^{^{'}} = 7 y