What is the integral of (cos^2(x))/(sin^2(x)) ?

The integral of (cos^2(x))/(sin^2(x)) is -cot(x)-x+C

integral of (cos^2(x))/(sin^2(x))

\int \frac{cos ^{2} ( x )}{sin ^{2} ( x )} d x

- cot (x) - x + C

Solution steps

\int \frac{cos ^{2} ( x )}{sin ^{2} ( x )} d x

Rewrite using trig identities

= \int \frac{1 - sin ^{2} ( x )}{sin ^{2} ( x )} d x

Expand

\frac{1 - sin ^{2} ( x )}{sin ^{2} ( x )} : \frac{1}{sin ^{2} ( x )} - 1

= \int \frac{1}{sin ^{2} ( x )} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{sin ^{2} ( x )} d x - \int 1 d x

\int \frac{1}{sin ^{2} ( x )} d x = - cot (x)

\int 1 d x = x

= - cot (x) - x

Add a constant to the solution

= - cot (x) - x + C

\frac{d}{d x} (7 x^{2} - 5 x + 3)

d er i v a t i v e \frac{( 3 e ^{3 x} )}{3}

\int \frac{1}{x ^{2} - 5 x + 4} d x

\int x x^{4} d x

\int \frac{x ^{3}}{8} d x

What is the integral of (cos^2(x))/(sin^2(x)) ?
The integral of (cos^2(x))/(sin^2(x)) is -cot(x)-x+C