What is (\partial}{\partial x}(\frac{x^4)/y) ?

The answer to (\partial}{\partial x}(\frac{x^4)/y) is (4x^3)/y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial}{\partial x}(\frac{x^4)/y)

\frac{\partial}{\partial x} (\frac{x ^{4}}{y})

\frac{4 x ^{3}}{y}

Solution steps

\frac{\partial}{\partial x} (\frac{x ^{4}}{y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{y} \frac{\partial}{\partial x} (x^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{y} \cdot 4 x^{4 - 1}

Simplify

\frac{1}{y} \cdot 4 x^{4 - 1} : \frac{4 x ^{3}}{y}

= \frac{4 x ^{3}}{y}

\frac{\partial}{\partial y} (6 + x ln (x y - 5))

\int 3 sin^{3} (x) cos^{7} (x) d x

x = 16 - y^{2}, x = y^{2} - 16

n = 6 \sum \infty \frac{3 n}{12 n}

y^{^{'''}} + y^{^{'}} = 2 x^{2}

What is (\partial}{\partial x}(\frac{x^4)/y) ?
The answer to (\partial}{\partial x}(\frac{x^4)/y) is (4x^3)/y