What is the derivative of 4cos(x-e^{2x}) ?

The derivative of 4cos(x-e^{2x}) is -4sin(x)-e^{2x}*2

What is the first derivative of 4cos(x-e^{2x}) ?

The first derivative of 4cos(x-e^{2x}) is -4sin(x)-e^{2x}*2

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\frac{d}{d x} (4 cos (x) - e^{2 x})

- 4 sin (x) - e^{2 x} \cdot 2

Solution steps

\frac{d}{d x} (4 cos (x) - e^{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 cos (x)) - \frac{d}{d x} (e^{2 x})

\frac{d}{d x} (4 cos (x)) = - 4 sin (x)

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

= - 4 sin (x) - e^{2 x} \cdot 2

sin^{2} (x)

\int x e^{x^{2} + 2} d x

x \to 4 - lim (ln (x - 4))

\int - e^{- 4 x} d x

\frac{d}{d x} ((3 x + 4)^{2})

What is the derivative of 4cos(x-e^{2x}) ?
The derivative of 4cos(x-e^{2x}) is -4sin(x)-e^{2x}*2
What is the first derivative of 4cos(x-e^{2x}) ?
The first derivative of 4cos(x-e^{2x}) is -4sin(x)-e^{2x}*2