What is the derivative of f(x)=x^4-4x^2+4 ?

The derivative of f(x)=x^4-4x^2+4 is 4x^3-8x

What is the first derivative of f(x)=x^4-4x^2+4 ?

The first derivative of f(x)=x^4-4x^2+4 is 4x^3-8x

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derivative of

f (x) = x^{4} - 4 x^{2} + 4

4 x^{3} - 8 x

Solution steps

\frac{d}{d x} (x^{4} - 4 x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (4) = 0

= 4 x^{3} - 8 x + 0

Simplify

= 4 x^{3} - 8 x

\frac{d}{d x} (sin (ln (tan (x))))

\int 6 t d t

y = (x + \frac{1}{x}) (x - \frac{1}{x})

\frac{d}{d x} (\frac{cos ( x ^{3} )}{e ^{x}})

f (x) = x^{2} - 4

What is the derivative of f(x)=x^4-4x^2+4 ?
The derivative of f(x)=x^4-4x^2+4 is 4x^3-8x
What is the first derivative of f(x)=x^4-4x^2+4 ?
The first derivative of f(x)=x^4-4x^2+4 is 4x^3-8x