What is the derivative of 5sin(x+x^2) ?

The derivative of 5sin(x+x^2) is 5cos(x)+2x

What is the first derivative of 5sin(x+x^2) ?

The first derivative of 5sin(x+x^2) is 5cos(x)+2x

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\frac{d}{d x} (5 sin (x) + x^{2})

5 cos (x) + 2 x

Solution steps

\frac{d}{d x} (5 sin (x) + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 sin (x)) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (5 sin (x)) = 5 cos (x)

\frac{d}{d x} (x^{2}) = 2 x

= 5 cos (x) + 2 x

\frac{d}{d t} (740 (1.714)^{t})

\frac{d}{d x} (c \cdot e^{x})

\int 4 + (e^{x} - e^{- x})^{2} d x

f (x) = - \frac{8}{( 1 + 4 x ) ^{2}}

\int (t^{2} + 1) e^{t^{3} + 3 t} d t

What is the derivative of 5sin(x+x^2) ?
The derivative of 5sin(x+x^2) is 5cos(x)+2x
What is the first derivative of 5sin(x+x^2) ?
The first derivative of 5sin(x+x^2) is 5cos(x)+2x