derivative of ((-sin(x)/(1-cos(x)))^2)

Lösung

\frac{d}{d x} ((\frac{- sin ( x )}{1 - cos ( x )})^{2})

\frac{2 sin ( x )}{( 1 - cos ( x ) ) ( cos ( x ) - 1 )}

Schritte zur Lösung

\frac{d}{d x} ((\frac{- sin ( x )}{1 - cos ( x )})^{2})

Wende die Kettenregel an:

2 \cdot \frac{- sin ( x )}{1 - cos ( x )} \frac{d}{d x} (\frac{- sin ( x )}{1 - cos ( x )})

= 2 \cdot \frac{- sin ( x )}{1 - cos ( x )} \frac{d}{d x} (\frac{- sin ( x )}{1 - cos ( x )})

\frac{d}{d x} (\frac{- sin ( x )}{1 - cos ( x )}) = - \frac{1}{cos ( x ) - 1}

= 2 \cdot \frac{- sin ( x )}{1 - cos ( x )} (- \frac{1}{cos ( x ) - 1})

Vereinfache

2 \cdot \frac{- sin ( x )}{1 - cos ( x )} (- \frac{1}{cos ( x ) - 1}) : \frac{2 sin ( x )}{( 1 - cos ( x ) ) ( cos ( x ) - 1 )}

= \frac{2 sin ( x )}{( 1 - cos ( x ) ) ( cos ( x ) - 1 )}

\int x (x - 1) d x

\frac{d}{d x} (\frac{( 1 - x ^{2} )}{1 + x ^{2}})

\frac{\partial}{\partial x} (\frac{m \cdot x \cdot T}{A})

x \to 1 + lim (7 ∣ x + 1 ∣ - 4)

\int_{0}^{3} 9 + x^{2} d x