What is (\partial)/(\partial y)(x/z+y/z) ?

The answer to (\partial)/(\partial y)(x/z+y/z) is 1/z

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(\partial)/(\partial y)(x/z+y/z)

\frac{\partial}{\partial y} (\frac{x}{z} + \frac{y}{z})

\frac{1}{z}

Solution steps

\frac{\partial}{\partial y} (\frac{x}{z} + \frac{y}{z})

Treat

x, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (\frac{x}{z}) + \frac{\partial}{\partial y} (\frac{y}{z})

\frac{\partial}{\partial y} (\frac{x}{z}) = 0

\frac{\partial}{\partial y} (\frac{y}{z}) = \frac{1}{z}

= 0 + \frac{1}{z}

Simplify

= \frac{1}{z}

\frac{s}{( s + 2 )}

y^{^{'}} = \frac{y}{x}, y (2) = 2

\frac{d}{d x} (e^{- ∣ x ∣})

x \to - 2 lim (\frac{x + 2}{2 x + 4})

What is (\partial)/(\partial y)(x/z+y/z) ?
The answer to (\partial)/(\partial y)(x/z+y/z) is 1/z