What is the solution for y^'+y/(9.33)=6.429 ?

The solution for y^'+y/(9.33)=6.429 is y=-e^{(-100t-c_{1})/(933)}+59.98257

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+y/(9.33)=6.429

y^{^{'}} + \frac{y}{9.33} = 6.429

y = - e^{\frac{- 100 t - c _{1}}{933}} + 59.98257

Solution steps

y^{'} (t) + \frac{y}{9.33} = 6.429

Solve separable ODE:

y = - e^{\frac{- 100 t - c _{1}}{933}} + 59.98257

y = - e^{\frac{- 100 t - c _{1}}{933}} + 59.98257

y^{^{''}} = x^{4}

\frac{s}{s + 3}

\frac{d x}{d t} = \frac{x ^{2} + t 9 t ^{2} + x ^{2}}{t x}

\frac{( 1 + x )}{1 - x}

\frac{d}{d x} (\frac{3}{4} x)

What is the solution for y^'+y/(9.33)=6.429 ?
The solution for y^'+y/(9.33)=6.429 is y=-e^{(-100t-c_{1})/(933)}+59.98257