What is laplacetransform s+1 ?

The answer to laplacetransform s+1 is 1/(s^2)+1/s

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laplacetransform s+1

laplace transform

s + 1

\frac{1}{s ^{2}} + \frac{1}{s}

Solution steps

L {s + 1}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {s} + L {1}

L {s} : \frac{1}{s ^{2}}

L {1} : \frac{1}{s}

= \frac{1}{s ^{2}} + \frac{1}{s}

\int (4 x + 1)^{5} d x

x + 9

\int_{0}^{3} 2 π x (3 x) d x

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\int cos^{7} (4 x) d x

What is laplacetransform s+1 ?
The answer to laplacetransform s+1 is 1/(s^2)+1/s