derivative of 3x^2+3x+cos(x)

Lösung

\frac{d}{d x} (3 x^{2} + 3 x + cos (x))

6 x + 3 - sin (x)

Schritte zur Lösung

\frac{d}{d x} (3 x^{2} + 3 x + cos (x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (cos (x))

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (cos (x)) = - sin (x)

= 6 x + 3 - sin (x)

\int tan^{7} (x) sec^{3} (x) d x

\frac{d}{d x} (\frac{sin ( x )}{x ^{2} - 1})

t an g e n t y = 14 x sin (x), (\frac{π}{2}, 7 π)

x \to \infty lim (xx)

\int 3 cos^{3} (6 x) d x