What is (\partial)/(\partial z)(y+z) ?

The answer to (\partial)/(\partial z)(y+z) is 1

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(\partial)/(\partial z)(y+z)

\frac{\partial}{\partial z} (y + z)

1

Solution steps

\frac{\partial}{\partial z} (y + z)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (y) + \frac{\partial}{\partial z} (z)

\frac{\partial}{\partial z} (y) = 0

\frac{\partial}{\partial z} (z) = 1

= 0 + 1

Simplify

= 1

f (x) = 2 x + x

\frac{d}{d x} (sin (x^{2} + 3 x + 1))

y = arcsin (x + 1)

\int \frac{2}{3} x^{\frac{3}{2}} - 9 sin (x) d x

\frac{\partial}{\partial x} (7 x sin (y - z))

What is (\partial)/(\partial z)(y+z) ?
The answer to (\partial)/(\partial z)(y+z) is 1