integral from-infinity to 0 of 1/(6-2x)

解答

\int_{- \infty}^{0} \frac{1}{6 - 2 x} d x

发散

求解步骤

\int_{- \infty}^{0} \frac{1}{6 - 2 x} d x

计算不定积分:

\int \frac{1}{6 - 2 x} d x = - \frac{1}{2} ln ∣ 6 - 2 x ∣ + C

带入上下限计算后得:

\int_{- \infty}^{0} \frac{1}{6 - 2 x} d x =

发散

= 发散

\frac{d}{d x} (\frac{3}{1 - x ^{2}})

\frac{\partial}{\partial x} (\frac{M}{2 p x})

x \to 3 lim (3 x^{4} + 2 x^{2} - 5)

f (x) = (- 3 x^{2} + 2 x + 4)^{12}

\frac{d}{d x} (1 - 169 x^{2} arccos (13 x))