What is the limit as x approaches 4 of 2x^4-x^2-8x ?

The limit as x approaches 4 of 2x^4-x^2-8x is 464

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limit as x approaches 4 of 2x^4-x^2-8x

x \to 4 lim (2 x^{4} - x^{2} - 8 x)

464

Solution steps

x \to 4 lim (2 x^{4} - x^{2} - 8 x)

Plug in the value

x = 4

= 2 \cdot 4^{4} - 4^{2} - 8 \cdot 4

Simplify

2 \cdot 4^{4} - 4^{2} - 8 \cdot 4 : 464

= 464

\frac{\partial}{\partial x} (\frac{3}{3 x + 5 y})

6 x^{2} ln (x), 24 ln (x)

\frac{d y}{d x} = \frac{1}{2} x + 2

x^{2} y^{^{''}} + 3 x y^{^{'}} + 2 y = 0, y (1) = 0.2, y^{^{'}} (1) = 0.3

What is the limit as x approaches 4 of 2x^4-x^2-8x ?
The limit as x approaches 4 of 2x^4-x^2-8x is 464