What is the integral of sin(x-2) ?

The integral of sin(x-2) is xsin(x-2)+xsin(2-x)-cos(2-x)+C

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integral of sin(x-2)

\int sin (x - 2) d x

x sin (x - 2) + x sin (2 - x) - cos (2 - x) + C

Solution steps

\int sin (x - 2) d x

Apply Integration By Parts

: sin (x - 2) x - \int cos (x - 2) x d x

= sin (x - 2) x - \int cos (x - 2) x d x

\int cos (x - 2) x d x = - x sin (2 - x) + cos (2 - x)

= sin (x - 2) x - (- x sin (2 - x) + cos (2 - x))

Simplify

sin (x - 2) x - (- x sin (2 - x) + cos (2 - x)) : x sin (x - 2) + x sin (2 - x) - cos (2 - x)

= x sin (x - 2) + x sin (2 - x) - cos (2 - x)

Add a constant to the solution

= x sin (x - 2) + x sin (2 - x) - cos (2 - x) + C

\frac{18}{x}

\int \frac{x ^{3}}{x ^{2} + 2} d x

\int e^{- (x^{2} + 1)} d x

y^{^{''}} + 4 y = cos (4 x), y (0) = 0, y^{^{'}} (0) = 0

\frac{\partial}{\partial x} (13 (3^{x}))

What is the integral of sin(x-2) ?
The integral of sin(x-2) is xsin(x-2)+xsin(2-x)-cos(2-x)+C