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Popular >

y^'+5xy=0

Solution

y^{^{'}} + 5 x y = 0

Solution

y = e^{- \frac{5 x ^{2}}{2} + c_{1}}

Solution steps

y^{'} (x) + 5 x y = 0

Solve separable ODE:

y = e^{- \frac{5 x ^{2}}{2} + c_{1}}

y = e^{- \frac{5 x ^{2}}{2} + c_{1}}

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\int \frac{- 3}{( x ^{2} + 3 ) ^{\frac{3}{2}}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+5xy=0 ?
The solution for y^'+5xy=0 is y=e^{-(5x^2)/2+c_{1}}