What is the solution for -y+(dy)/(dx)ln(x)=0 ?

The solution for -y+(dy)/(dx)ln(x)=0 is y=e^{\Ei(ln(x))+c_{1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

-y+(dy)/(dx)ln(x)=0

- y + \frac{d y}{d x} ln (x) = 0

y = e^{Ei (l n (x)) + c_{1}}

Solution steps

- y + \frac{d y}{d x} ln (x) = 0

Solve separable ODE:

y = e^{Ei (l n (x)) + c_{1}}

y = e^{Ei (l n (x)) + c_{1}}

\frac{d}{d x} (arcsin (x^{2} + 1))

t an g e n t y = \frac{x}{36 + x ^{2}}, (0, 0)

p a r i t y f (t) = tan (sec (cos (t)))

x \to 5 lim (76)

\int_{- 5}^{7} (\frac{x}{2} + 7) d x

What is the solution for -y+(dy)/(dx)ln(x)=0 ?
The solution for -y+(dy)/(dx)ln(x)=0 is y=e^{\Ei(ln(x))+c_{1}}