What is the solution for dx-x+ydy=0 ?

The solution for dx-x+ydy=0 is y=sqrt(x^2-2x+c_{1)},y=-sqrt(x^2-2x+c_{1)}

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dx-x+ydy=0

d x - x + y d y = 0

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

Solution steps

d x - x + y d y = 0

Solve separable ODE:

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

y = x^{2} - 2 x + c_{1}, y = - x^{2} - 2 x + c_{1}

\int e^{17 x} d x

\frac{\partial}{\partial y} (3 x yz + x y^{2} - x z^{3})

42 y^{^{''}} + 29 y^{^{'}} - 5 y = 0

n = 1 \sum \infty \frac{n}{( 3 + n )}

\frac{d}{d x} (ln (3 x^{3} + x + 6))

What is the solution for dx-x+ydy=0 ?
The solution for dx-x+ydy=0 is y=sqrt(x^2-2x+c_{1)},y=-sqrt(x^2-2x+c_{1)}