What is the tangent of-2x^3 ?

The tangent of-2x^3 is y=-6a_{0}^2x+4a_{0}^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of-2x^3

tangent of

- 2 x^{3}

y = - 6 a_{0}^{2} x + 4 a_{0}^{3}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 2 a_{0}^{3})

Find the slope of

y = - 2 x^{3} : \frac{d y}{d x} = - 6 x^{2}

Compute the slope of

y = - 2 x^{3}

x = a_{0} : m = - 6 a_{0}^{2}

Find the line with slope m=

- 6 a_{0}^{2}

and passing through

(a_{0}, - 2 a_{0}^{3}) : y = - 6 a_{0}^{2} x + 4 a_{0}^{3}

y = - 6 a_{0}^{2} x + 4 a_{0}^{3}

\frac{d y}{d x} + y = 1

\int 2 x^{7} d x

\frac{d ^{2}}{d x ^{2}} ((ln (x))^{2})

y = \frac{( x + 1 )}{x ^{3} + x - 2}

\frac{d}{d x} (e^{4 x y})