What is the derivative of-(2x/y) ?

The derivative of-(2x/y) is -(2(y-x\frac{dy)/(dx))}{y^2}

What is the first derivative of-(2x/y) ?

The first derivative of-(2x/y) is -(2(y-x\frac{dy)/(dx))}{y^2}

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Popular >

\frac{d}{d x} (- \frac{2 x}{y})

- \frac{2 ( y - x \frac{d y}{d x} )}{y ^{2}}

Solution steps

\frac{d}{d x} (- \frac{2 x}{y})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (\frac{x}{y})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - 2 \cdot \frac{\frac{d x}{d x} y - \frac{d y}{d x} x}{y ^{2}}

\frac{d x}{d x} = 1

= - 2 \cdot \frac{1 \cdot y - \frac{d y}{d x} x}{y ^{2}}

Simplify

- 2 \cdot \frac{1 \cdot y - \frac{d y}{d x} x}{y ^{2}} : - \frac{2 ( y - x \frac{d y}{d x} )}{y ^{2}}

= - \frac{2 ( y - x \frac{d y}{d x} )}{y ^{2}}

\int \frac{4 x ^{2} - 25}{x} d x

(- 6, 1), (- 4, - 9)

\frac{d}{d x} (4 x + 2)

\int \frac{2}{x ^{2} + 4} d x

y = \frac{1}{3} x^{3} + 2, y = x + 1, 0, 2

What is the derivative of-(2x/y) ?
The derivative of-(2x/y) is -(2(y-x\frac{dy)/(dx))}{y^2}
What is the first derivative of-(2x/y) ?
The first derivative of-(2x/y) is -(2(y-x\frac{dy)/(dx))}{y^2}